UVa 488 - Triangle Wave

In this problem you are to generate a triangular wave form according to a specified pair of Amplitude and Frequency.

 

Input and Output

The input begins with a single positive integer on a line by itself indicating the number of the cases following, each of them as described below. This line is followed by a blank line, and there is also a blank line between two consecutive inputs.

Each input set will contain two integers, each on a separate line. The first integer is the Amplitude; the second integer is the Frequency.

For each test case, the output must follow the description below. The outputs of two consecutive cases will be separated by a blank line.

For the output of your program, you will be printing wave forms each separated by a blank line. The total number of wave forms equals the Frequency, and the horizontal ``height'' of each wave equals the Amplitude. The Amplitude will never be greater than nine.

The waveform itself should be filled with integers on each line which indicate the ``height'' of that line.

NOTE: There is a blank line after each separate waveform, excluding the last one.

Sample Input

 

1

3
2

Sample Output

 

1
22
333
22
1

1
22
333
22
1


题义：打印图形。输入一个数T，表示测试数据，输入空行（貌似没用），输入n、m，n表示振幅，m表示输出的组数。最后没有空行。
AC代码如下：

#include<stdio.h>
#include<math.h>
int main()
{
    int T, n, m, i, j;
    scanf("%d", &T);
    while(T--)
    {
        scanf("%d%d", &n, &m);
        while(m--)
        {
            for (i=1-n; i<n; i++)
            {
                for (j=1; j<=n-(abs(i)); j++)
                {
                    printf("%d", n-(abs(i)));
                }
                printf("\n");
            }
            if (m)
                printf("\n");
        }
        if (T)
            printf("\n");
    }
    return 0;
}