zhber
有好多做过的题没写下来,如果我还能记得就补吧

 

B. Fedor and New Game
time limit per test
1 second
memory limit per test
256 megabytes
input
standard input
output
standard output

After you had helped George and Alex to move in the dorm, they went to help their friend Fedor play a new computer game «Call of Soldiers 3».

The game has (m + 1) players and n types of soldiers in total. Players «Call of Soldiers 3» are numbered form 1 to (m + 1). Types of soldiers are numbered from 0 to n - 1. Each player has an army. Army of the i-th player can be described by non-negative integer xi. Consider binary representation of xi: if the j-th bit of number xi equal to one, then the army of the i-th player has soldiers of the j-th type.

Fedor is the (m + 1)-th player of the game. He assume that two players can become friends if their armies differ in at most k types of soldiers (in other words, binary representations of the corresponding numbers differ in at most k bits). Help Fedor and count how many players can become his friends.

Input

The first line contains three integers nmk (1 ≤ k ≤ n ≤ 20; 1 ≤ m ≤ 1000).

The i-th of the next (m + 1) lines contains a single integer xi (1 ≤ xi ≤ 2n - 1), that describes the i-th player's army. We remind you that Fedor is the (m + 1)-th player.

Output

Print a single integer — the number of Fedor's potential friends.

Sample test(s)
input
7 3 1
8
5
111
17
output
0
input
3 3 3
1
2
3
4
output
3

 

sb题*2

给m个数,转成二进制,问和给定的x的每一位异或和小等于k的有多少个

#include<iostream>
#include<cstring>
#include<cstdio>
using namespace std;
int n,m,k,ans,a[100100];
int work(int x)
{
    int res=0;
    for(int i=0;i<=21;i++)
     if((x&(1<<i))^(m&(1<<i)))res++;
    return res;
}
int main()
{
    scanf("%d%d%d",&m,&n,&k);
    int x,y;
    for(int i=1;i<=n;i++)
        scanf("%d",&a[i]);
    scanf("%d",&m);
    for(int i=1;i<=n;i++)
        if(work(a[i])<=k)ans++;
    printf("%d",ans);
    return 0;
}

  

posted on 2014-09-19 16:23  zhber  阅读(246)  评论(0编辑  收藏  举报