const setA = new Set([1, 2, 4, 5])
const setB = new Set([5,4, 3])
// 并集
res = new Set([...setA, ...setB])
// 交集
res = new Set([...setA].filter( item => setB.has(item)))
// 差集
res = new Set([...setA].filter( item => !setB.has(item)))
console.log(res)
posted on
2021-08-18 09:48yyy_鸳鸯
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