溪语
Less Is More
Input: "Let's take LeetCode contest"
Output: "s'teL ekat edoCteeL tsetnoc"

解:输入一堆字符串,每一个空格之前的字符串都要反转,拆成一个数组反转之后拼成一个字符串
let array = s.split(' ');
    let newArr = [];
    for(let i = 0; i < array.length; i++){
        let str = array[i].split("").reverse().join("")
        newArr.push(str)
    }
    let newStr = ''
    for(let j = 0; j<newArr.length; j++){
        if(j == newArr.length-1){
            newStr = newStr + newArr[j]
        }else{
            newStr = newStr + newArr[j] + " "
        }
        
    }
    return newStr

  

posted on 2018-07-03 15:19  溪语_8023  阅读(93)  评论(0编辑  收藏  举报