1、首先获取一个最近1000天的时间列表,如果不够可以按规则再加

SELECT   adddate(CURDATE(),-(t2.i * 100 + t1.i * 10 + t0.i)) date 
 FROM (SELECT 0 i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9 ) t0,
    (SELECT 0 i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) t1,
    (SELECT 0 i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) t2

2、然后获取最近30天的开始时间 DATE_SUB(CURDATE(), INTERVAL 30 DAY)

3、最后截取最近30天的时间,在步骤1的外面包一层然后 BETWEEN DATE_SUB(CURDATE(), INTERVAL 30 DAY)  AND CURDATE()就可以了。

SELECT * FROM 
(SELECT
adddate(CURDATE(),-(t2.i * 100 + t1.i * 10 + t0.i)) date
FROM (SELECT 0 i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9 ) t0, (SELECT 0 i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) t1, (SELECT 0 i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) t2) date
WHERE date.date BETWEEN DATE_SUB(CURDATE(), INTERVAL 30 DAY)  AND CURDATE();

 

效果是

 

posted on 2021-10-13 18:15  程序员丁先生  阅读(684)  评论(0编辑  收藏  举报