Leetcode 36. 有效的数独(可以,一次过)
请你判断一个 9 x 9 的数独是否有效。只需要 根据以下规则 ,验证已经填入的数字是否有效即可。
- 数字 1-9 在每一行只能出现一次。
- 数字 1-9 在每一列只能出现一次。
- 数字 1-9 在每一个以粗实线分隔的 3x3 宫内只能出现一次。(请参考示例图)
注意:
- 一个有效的数独(部分已被填充)不一定是可解的。
- 只需要根据以上规则,验证已经填入的数字是否有效即可。
- 空白格用 '.' 表示。
示例 1:
输入:board = [["5","3",".",".","7",".",".",".","."] ,["6",".",".","1","9","5",".",".","."] ,[".","9","8",".",".",".",".","6","."] ,["8",".",".",".","6",".",".",".","3"] ,["4",".",".","8",".","3",".",".","1"] ,["7",".",".",".","2",".",".",".","6"] ,[".","6",".",".",".",".","2","8","."] ,[".",".",".","4","1","9",".",".","5"] ,[".",".",".",".","8",".",".","7","9"]] 输出:true
示例 2:
输入:board = [["8","3",".",".","7",".",".",".","."] ,["6",".",".","1","9","5",".",".","."] ,[".","9","8",".",".",".",".","6","."] ,["8",".",".",".","6",".",".",".","3"] ,["4",".",".","8",".","3",".",".","1"] ,["7",".",".",".","2",".",".",".","6"] ,[".","6",".",".",".",".","2","8","."] ,[".",".",".","4","1","9",".",".","5"] ,[".",".",".",".","8",".",".","7","9"]] 输出:false 解释:除了第一行的第一个数字从 5 改为 8 以外,空格内其他数字均与 示例1 相同。 但由于位于左上角的 3x3 宫内有两个 8 存在, 因此这个数独是无效的。
提示:
- board.length == 9
- board[i].length == 9
- board[i][j] 是一位数字(1-9)或者 '.'
主要思路:map
Code:
class Solution { public: bool isValidSudoku(vector<vector<char>>& board) { map<char,int>mymap; pair<map<char, int>::iterator, bool> ret; for(int j=0;j<board[0].size();j++) { for(int i=0;i<board.size();i++) { vector<char>sub=board[i]; if(board[i][j]=='.') continue; ret=mymap.insert(pair<char,int>(board[i][j],0)); if(!ret.second) return false; cout<<board[i][j]<<endl; } mymap.clear(); } mymap.clear(); for(int i=0;i<board.size();i++) { vector<char>sub=board[i]; for(int j=0;j<sub.size();j++) { if(sub[j]=='.') continue; ret=mymap.insert(pair<char,int>(sub[j],0)); if(!ret.second) return false; } mymap.clear(); } mymap.clear(); cout<<"++++"<<endl; int row=0; int col=0; do { for(int i=row;i<row+3;i++) { vector<char>sub=board[i]; for(int j=col;j<col+3;j++) { if(sub[j]=='.') continue; ret=mymap.insert(pair<char,int>(sub[j],0)); if(!ret.second) return false; } } col+=3; mymap.clear(); if(col==9) { col=0; row+=3; cout<<"row="<<row<<endl; } if(row==9) { break; } }while(1); return true; } };
分类:
C/C++
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