摘要: 方法一:(效率最高)select * from test as a where typeindex = (select max(b.typeindex) from test as b where a.type = b.type );方法二:(效率次之)select a.* from test a,( 阅读全文
posted @ 2017-08-30 13:50 vofill-work 阅读(6051) 评论(2) 推荐(2) 编辑