方法一:(效率最高)
select * from test as a 
where typeindex = (select max(b.typeindex) 
from test as b 
where a.type = b.type );


方法二:(效率次之)
select 
a.* from test a,
(select type,max(typeindex) typeindex from test group by type) b 
where a.type = b.type and a.typeindex = b.typeindex order by a.type 




方法三:
select a.* from test a inner join (select type , max(typeindex) typeindex from test group by type) b on a.type = b.type and a.typeindex = b.typeindex order by a.type


方法四:(效率最低)
select * from
(
select *,ROW_NUMBER() OVER(PARTITION BY type ORDER BY typeindex DESC) as num
from test
) t
where t.num = 1

posted on 2017-08-30 13:50  vofill-work  阅读(6051)  评论(2编辑  收藏  举报