方法一:
#include <iostream>
#include <windows.h>
#include <string>
using namespace std;
int main() {
int i = 0, j = 0;
int a[4][5];
//给数组成员赋值
for (int i = 0; i < 20; i++) {
a[i / 5][i % 5] = i + 1;
}
//输出数值
for (int i = 0; i < 4; i++) {
for (int j = 0; j < 5; j++) {
printf("%d ", a[i][j]);
}
printf("\n");
}
system("pause");
return 0;
}
方法二:
#include <iostream>
#include <windows.h>
#include <string>
using namespace std;
int main() {
int i = 0, j = 0;
int a[4][5];
//给数组成员赋值
for (int i = 0; i < 4; i++) {
for (int j = 0; j < 5; j++) {
a[i][j] = 5 * i + j + 1;
}
}
for (int i = 0; i < 4; i++) {
for (int j = 0; j < 5; j++) {
printf("%d ",a[i][j]);
}
printf("\n");
}
system("pause");
return 0;
}