/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */
class Solution {
    public boolean isSubtree(TreeNode s, TreeNode t) {
        if (s == null) {
            return false;
        }
        
        if (doesMatch(s, t)) {
            return true;
        }
        
        return isSubtree(s.left, t) || isSubtree(s.right, t);
    }
    
    private boolean doesMatch(TreeNode s, TreeNode t) {
        if (s == null && t == null) {
            return true;
        }
        
        if (s == null || t == null) {
            return false;
        }
        return s.val == t.val && doesMatch(s.left, t.left) && doesMatch(s.right, t.right);
    }
}

 

posted on 2017-09-03 06:31  keepshuatishuati  阅读(79)  评论(0编辑  收藏  举报