题目描述:
Given a binary tree, find its minimum depth.
The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node.
本题要我们写一个找二叉树最小深度分叉的函数,返回最小深度。
解题思路:
本题的解题思路可以参考找二叉树最大深度那题的函数。用递归比较当前节点下两个分支的深度,返回较小深度。
代码:
1 /** 2 * Definition for a binary tree node. 3 * struct TreeNode { 4 * int val; 5 * TreeNode *left; 6 * TreeNode *right; 7 * TreeNode(int x) : val(x), left(NULL), right(NULL) {} 8 * }; 9 */ 10 class Solution { 11 public: 12 int minDepth(TreeNode* root) { 13 if(!root) 14 return 0; 15 else if(!root->left) 16 return minDepth(root->right)+1; 17 else if(!root->right) 18 return minDepth(root->left)+1; 19 else 20 return min(minDepth(root->left),minDepth(root->right))+1; 21 } 22 };