[关键字]:枚举
[题目大意]:给出每个字母的分数,
//================================================================================================================
[分析]:一开始想了半天hash也没想对,这题居然枚举就能做。虽然给出的字典很大,但是其实有用的词很少。只要在读入字典时判断一下是否是由给出的字符中的一些组成,然后之久枚举超找最大值和词组就行。
[代码]:
View Code
/*
ID:procedure2
PROB:lgame
LANG:C++
*/
#include<iostream>
#include<cstdio>
#include<cstdlib>
#include<cstring>
#include<algorithm>
using namespace std;
const int value[26]={2,5,4,4,1,6,5,5,1,7,6,3,5,2,3,5,7,2,1,2,4,6,6,7,5,7};
int tot,a[26],b[26],ans,sum;
char s[10],s1[20],s2[20][20],word[40000][10];
bool Cleck(char *s)
{
int len=strlen(s);
memcpy(b,a,sizeof(a));
for (int i=0;i<len;i++)
if (s[i]!=' ') b[s[i]-'a']--;
for (int i=0;i<26;i++)
if (b[i]<0) return 0;
return 1;
}
void Init()
{
freopen("lgame.in","r",stdin);
freopen("lgame.out","w",stdout);
scanf("%s",s);
for (int i=0;i<strlen(s);i++) a[s[i]-'a']++;
fclose(stdin);
freopen("lgame.dict","r",stdin);
while (1)
{
scanf("%s",s1);
//printf("%s\n",s1);
if (s1[0]=='.') break;
if (Cleck(s1)) strcpy(word[++tot],s1);
}
fclose(stdin);
//printf("%d\n",tot);
//for (int i=1;i<=tot;i++) printf("%s\n",word[i]);
}
int sorce(char *s)
{
int sum=0;
for (int i=0;i<strlen(s);i++)
if (s[i]!=' ') sum+=value[s[i]-'a'];
return sum;
}
bool cmp(char *a,char *b)
{
if (strcmp(a,b)<0) return 1; else return 0;
}
void Solve()
{
for (int i=1;i<=tot;i++)
{
int temp=sorce(word[i]);
if (temp==ans) strcpy(s2[++sum],word[i]);
if (temp>ans) ans=temp,strcpy(s2[sum=1],word[i]);
}
for (int i=1;i<tot;i++)
for (int j=i+1;j<=tot;j++)
{
strcpy(s1,word[i]);
strcat(s1," ");
strcat(s1,word[j]);
//printf("%s\n",s1);
if (!Cleck(s1)) continue;
int temp=sorce(s1);
if (temp==ans) strcpy(s2[++sum],s1);
if (temp>ans) ans=temp,strcpy(s2[sum=1],s1);
}
printf("%d\n",ans);
for (int i=1;i<sum;i++)
for (int j=i+1;j<=sum;j++)
if (strcmp(s2[i],s2[j])>0)
{
strcpy(s1,s2[i]);
strcpy(s2[i],s2[j]);
strcpy(s2[j],s1);
}
for (int i=1;i<=sum;i++) printf("%s\n",s2[i]);
}
int main()
{
Init();
Solve();
return 0;
}