1、常规方法（可运用于SQL SERVER 2000中）
DECLARE @str varchar(1000)
DECLARE @idoc int;
DECLARE @doc xml;
set @str='aaa,bbb,ccc'
set @doc=cast('<Root>
<item><ID>'+replace(@str,',','
</ID></item><item><ID>')+'</ID></item></Root>' as xml)
EXEC sp_xml_preparedocument @Idoc OUTPUT, @doc
SELECT * FROM OPENXML (@Idoc, '/Root/item',2)
WITH (
[ID] varchar(10)
)
/**//*
ID
-----------
aaa
bbb
ccc
*/
2、运用SQL SERVER 2005 中的新类型xml
代码
declare @str varchar(1000)
declare @x xml
set @str='aaa,bbb,ccc'
SELECT @x = CONVERT(xml,
'<v>' + REPLACE(@str, ',', '</v><v>') + '</v>')
SELECT N.v.value('.', 'varchar(100)')
FROM @x.nodes('/v') N(v)
declare @x xml
set @str='aaa,bbb,ccc'
SELECT @x = CONVERT(xml,
'<v>' + REPLACE(@str, ',', '</v><v>') + '</v>')
SELECT N.v.value('.', 'varchar(100)')
FROM @x.nodes('/v') N(v)
3、运用SQL SERVER 2005 中的新类型xml及OUTER APPLY一句SQL搞定
代码
DECLARE @str VARCHAR(1000)
DECLARE @x xml
SET @str='aaa,bbb,ccc'
SELECT id
FROM (SELECT [value] = CONVERT(XML , '<v>' + REPLACE(@str , ',' , '</v><v>')+ '</v>')
) A
OUTER APPLY ( SELECT id = N.v.value('.' , 'varchar(100)')
FROM A.[value].nodes('/v') N (v)
) B
DECLARE @x xml
SET @str='aaa,bbb,ccc'
SELECT id
FROM (SELECT [value] = CONVERT(XML , '<v>' + REPLACE(@str , ',' , '</v><v>')+ '</v>')
) A
OUTER APPLY ( SELECT id = N.v.value('.' , 'varchar(100)')
FROM A.[value].nodes('/v') N (v)
) B
其实第二种与第三种是一样的，只不过第二种用了一个中间变量来处理
