fastle
垆边人似月 皓腕凝霜雪
/*
水题, 根据性质做就行, nq不会对答案产生贡献, 那么只算p的贡献就好了

*/

#include<cstdio>
#include<algorithm>
#include<cstring>
#include<queue>
#include<map>
#include<iostream>
#define ll long long
#define M 200020
#define mmp make_pair
using namespace std;
int read() {
	int nm = 0, f = 1;
	char c = getchar();
	for(; !isdigit(c); c = getchar()) if(c == '-') f = -1;
	for(; isdigit(c); c = getchar()) nm = nm * 10 + c - '0';
	return nm * f;
}
map<int, int> ch[M];
int fa[M], len[M], lst = 1, cnt = 1, n;
ll ans = 0;

void insert(int c) {
	int p = ++cnt, f = lst;
	lst = p;
	len[p] = len[f] + 1;
	while(f && !ch[f][c]) ch[f][c] = p, f = fa[f];
	if(f == 0) fa[p] = 1;
	else {
		int q = ch[f][c];
		if(len[q] == len[f] + 1) fa[p] = q;
		else {
			int nq = ++cnt;
			ch[nq] = ch[q];
			fa[nq] = fa[q];
			len[nq] = len[f] + 1;
			fa[p] = fa[q] = nq;
			while(f && ch[f][c] == q) ch[f][c] = nq, f = fa[f];
		}
	}
	ans += len[p] - len[fa[p]];
}

int main() {
	n = read();
	for(int i = 1; i <= n; i++) {
		insert(read());
		cout << ans << "\n";
	}
	return 0;
}
posted on 2019-04-11 06:57  fastle  阅读(101)  评论(0编辑  收藏  举报