程序媛詹妮弗

2019年5月4日

摘要： Suppose you have a long flowerbed in which some of the plots are planted and some are not. However, flowers cannot be planted in adjacent plots - they 阅读全文

posted @ 2019-05-04 06:20 程序媛詹妮弗阅读(242) 评论(0) 推荐(0) 编辑

2019年4月26日

[leetcode]432. All O`one Data Structure全O(1)数据结构

摘要： Implement a data structure supporting the following operations: Challenge: Perform all these in O(1) time complexity. 题意：设计一个类似hash map的计数器，但要提供最大值对应阅读全文

posted @ 2019-04-26 04:50 程序媛詹妮弗阅读(252) 评论(0) 推荐(0) 编辑

2019年4月25日

[leetcode]68. Text Justification文字对齐

摘要： Given an array of words and a width maxWidth, format the text such that each line has exactly maxWidth characters and is fully (left and right) justif 阅读全文

posted @ 2019-04-25 22:26 程序媛詹妮弗阅读(176) 评论(0) 推荐(0) 编辑

[leetcode]149. Max Points on a Line多点共线

摘要： Given n points on a 2D plane, find the maximum number of points that lie on the same straight line. Example 1: Example 2: NOTE: input types have been 阅读全文

posted @ 2019-04-25 21:58 程序媛詹妮弗阅读(297) 评论(0) 推荐(0) 编辑

[leetcode]272. Closest Binary Search Tree Value II二叉搜索树中最近的值II

摘要： Given a non-empty binary search tree and a target value, find k values in the BST that are closest to the target. Note: Given target value is a floati 阅读全文

posted @ 2019-04-25 13:40 程序媛詹妮弗阅读(186) 评论(0) 推荐(0) 编辑

LinkedIn TAG

摘要： 1 [leetcode]243. Shortest Word Distance最短单词距离 Two Pointers 2 [leetcode]244. Shortest Word Distance II最短单词距离(允许连环call) HashMap+Merge Sort 3 [leetcode]2 阅读全文

posted @ 2019-04-25 05:56 程序媛詹妮弗阅读(437) 评论(0) 推荐(0) 编辑

2019年4月23日

[leetcode]66. Plus One加一

摘要： Given a non-empty array of digits representing a non-negative integer, plus one to the integer. The digits are stored such that the most significant d 阅读全文

posted @ 2019-04-23 08:02 程序媛詹妮弗阅读(128) 评论(0) 推荐(0) 编辑

[leetcode]61. Rotate List旋转链表

摘要： Given a linked list, rotate the list to the right by k places, where k is non-negative. Example 1: Example 2: 题意：给定一个链表，循环移位k次。阅读全文

posted @ 2019-04-23 07:58 程序媛詹妮弗阅读(197) 评论(0) 推荐(0) 编辑

2019年4月20日

对palindrome的常用判断

摘要：判断String是否为palindrome：Two Pointers(left & right) 同时边扫边check 当前两边的char是否相同 code 判断number是否为palindrome：先reverse original number 变为reversed number ，再判断 o 阅读全文

posted @ 2019-04-20 07:58 程序媛詹妮弗阅读(319) 评论(0) 推荐(0) 编辑

理解StringBuilder

摘要： StringBuilder objects are like String objects, except that they can be modified. Internally, these objects are treated like variable-length arrays tha 阅读全文

posted @ 2019-04-20 07:04 程序媛詹妮弗阅读(358) 评论(0) 推荐(0) 编辑