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Design a data structure that supports all following operations in average O(1) time.

Note: Duplicate elements are allowed.

 

  1. insert(val): Inserts an item val to the collection.
  2. remove(val): Removes an item val from the collection if present.
  3. getRandom: Returns a random element from current collection of elements. The probability of each element being returned is linearly related to the number of same value the collection contains.

 

Example:

// Init an empty collection.
RandomizedCollection collection = new RandomizedCollection();

// Inserts 1 to the collection. Returns true as the collection did not contain 1.
collection.insert(1);

// Inserts another 1 to the collection. Returns false as the collection contained 1. Collection now contains [1,1].
collection.insert(1);

// Inserts 2 to the collection, returns true. Collection now contains [1,1,2].
collection.insert(2);

// getRandom should return 1 with the probability 2/3, and returns 2 with the probability 1/3.
collection.getRandom();

// Removes 1 from the collection, returns true. Collection now contains [1,2].
collection.remove(1);

// getRandom should return 1 and 2 both equally likely.
collection.getRandom();

 

Solution1: HashMap + ArrayList

  

 

 

 

code

 1 public class RandomizedCollection {
 2     class Node {
 3         public int value;
 4         public int index;
 5         public Node(int val, int idx) {
 6             value = val;
 7             index = idx;
 8         }
 9     }
10 
11     private Map<Integer, List<Integer>> map;
12     private List<Node> list;
13     private Random r;
14 
15     /** Initialize your data structure here. */
16     public RandomizedCollection() {
17         map = new HashMap<>();
18         list = new ArrayList<>();
19         r = new Random();
20     }
21 
22     /** Inserts a value to the collection. Returns true if the collection did not already contain the specified element. */
23     public boolean insert(int val) {
24         List<Integer> l = map.getOrDefault(val, new ArrayList<>());
25         l.add(list.size());
26         map.put(val, l);
27         list.add(new Node(val, l.size() - 1));
28         return l.size() == 1;
29     }
30 
31     /** Removes a value from the collection. Returns true if the collection contained the specified element. */
32     public boolean remove(int val) {
33         if (!map.containsKey(val)) return false;
34         List<Integer> l = map.get(val);
35         int removeIdx = l.get(l.size() - 1);
36         Node replaceNode = list.get(list.size() - 1);
37 
38         // deal with HashMap
39          map.get(replaceNode.value).set(replaceNode.index, removeIdx);
40          l.remove(l.size() - 1);
41          if (l.size() == 0) map.remove(val);
42 
43         // deal with List
44         list.set(removeIdx, replaceNode);
45         list.remove(list.size() - 1);
46         
47         return true;
48     }
49 
50     /** Get a random element from the collection. */
51     public int getRandom() {
52         return list.get(r.nextInt(list.size())).value;
53     }
54 }

 

posted on 2018-10-21 04:22  程序媛詹妮弗  阅读(100)  评论(0编辑  收藏  举报