程序媛詹妮弗
终身学习

Given a positive integer n, generate a square matrix filled with elements from 1 to n^2 in spiral order.

Example:

Input: 3
Output:
[
 [ 1, 2, 3 ],
 [ 8, 9, 4 ],
 [ 7, 6, 5 ]
]

 

题意:

给定n, 把1至n ^ 2所有的数,按照螺旋顺序填入方阵。

 

code

 1 /*
 2 Time: O(n^2)
 3 Space: O(n^2)
 4 */
 5 class Solution {
 6     public int[][] generateMatrix(int n) {
 7         int[][] matrix = new int[n][n];
 8         if (n == 0) return matrix;
 9         int beginX = 0, endX = n - 1;
10         int beginY = 0, endY = n - 1;
11         int num = 1;
12         while (true) {
13             for (int j = beginX; j <= endX; ++j) matrix[beginY][j] = num++;
14             if (++beginY > endY) break;
15 
16             for (int i = beginY; i <= endY; ++i) matrix[i][endX] = num++;
17             if (beginX > --endX) break;
18 
19             for (int j = endX; j >= beginX; --j) matrix[endY][j] = num++;
20             if (beginY > --endY) break;
21 
22             for (int i = endY; i >= beginY; --i) matrix[i][beginX] = num++;
23             if (++beginX > endX) break;
24         }
25         return matrix;
26     }
27 }

 

posted on 2018-10-18 06:28  程序媛詹妮弗  阅读(134)  评论(0编辑  收藏  举报