Say you have an array for which the ith element is the price of a given stock on day i.
If you were only permitted to complete at most one transaction (i.e., buy one and sell one share of the stock), design an algorithm to find the maximum profit.
Note that you cannot sell a stock before you buy one.
Example 1:
Input: [7,1,5,3,6,4] Output: 5 Explanation: Buy on day 2 (price = 1) and sell on day 5 (price = 6), profit = 6-1 = 5. Not 7-1 = 6, as selling price needs to be larger than buying price.
题目
给定一系列股价,允许买卖各一次。求最大收益。
思路
扫一遍input array,对于每个price: 更新当前minPrice, 更新当前maxProfit
代码
1 class Solution { 2 public int maxProfit(int[] prices) { 3 if(prices.length < 2) return 0; 4 int maxProfit = 0; 5 int minPrice = prices[0]; 6 for(int price : prices){ 7 minPrice = Math.min(minPrice, price); 8 maxProfit = Math.max(maxProfit, price - minPrice); 9 } 10 return maxProfit; 11 } 12 }
【推荐】国内首个AI IDE,深度理解中文开发场景,立即下载体验Trae
【推荐】编程新体验,更懂你的AI,立即体验豆包MarsCode编程助手
【推荐】抖音旗下AI助手豆包,你的智能百科全书,全免费不限次数
【推荐】轻量又高性能的 SSH 工具 IShell:AI 加持,快人一步