The Euler function
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 8008 Accepted Submission(s):
3336
Problem Description
The Euler function phi is an important kind of function
in number theory, (n) represents the amount of the numbers which are smaller
than n and coprime to n, and this function has a lot of beautiful
characteristics. Here comes a very easy question: suppose you are given a, b,
try to calculate (a)+ (a+1)+....+ (b)
Input
There are several test cases. Each line has two
integers a, b (2<a<b<3000000).
Output
Output the result of (a)+ (a+1)+....+ (b)
Sample Input
3 100
Sample Output
3042
Source
Recommend
欧拉函数挺有用的似乎,欧拉函数表和朴素筛法是有着异曲同工之妙的
1 #include "bits/stdc++.h" 2 using namespace std; 3 typedef long long LL; 4 const int MAX=3e6+5; 5 int phi[MAX]; 6 void eular(){ 7 int i,j; 8 for (i=1;i<MAX;i++) phi[i]=i; 9 for (i=2;i<MAX;i+=2) phi[i]/=2; 10 for (i=3;i<MAX;i+=2){ 11 if (phi[i]==i) 12 for (j=i;j<MAX;j+=i) 13 phi[j]=phi[j]/i*(i-1); 14 } 15 } 16 int main(){ 17 freopen ("euler.in","r",stdin); 18 freopen ("euler.out","w",stdout); 19 int i,j; 20 eular(); 21 LL x,y,ans; 22 while (~scanf("%lld%lld",&x,&y)){ 23 for (i=x,ans=0;i<=y;i++) ans+=(LL)phi[i]; 24 printf("%lld\n",ans); 25 } 26 return 0; 27 }
未来是什么样,未来会发生什么,谁也不知道。
但是我知道,
起码从今天开始努力,
肯定比从明天开始努力,
要快一天实现梦想。
千里之行,始于足下! ——《那年那兔那些事儿》