C语言一个数学问题：求s=(a^m)!+(b^n)!

求s=(a^m)!+(bⁿ)!

//凯鲁嘎吉 - 博客园 http://www.cnblogs.com/kailugaji/

 1 #include<stdio.h>
 2 void main(){
 3     int a, b, m, n, a_m, b_n, sum, power(int, int), fact(int), add(int, int);
 4     printf("Please input a, m, b, n :\n");
 5     scanf("%d %d %d %d", &a, &m, &b, &n);
 6     a_m=fact(power(a, m));    //a_m=(a^m)!
 7     b_n=fact(power(b, n));     //b_n=(b^n)!
 8     sum=add(a_m, b_n);
 9     printf("(%d^%d)!+(%d^%d)!=%d\n", a, m, b, n, sum);
10 }
11 //实现求和 x+y
12 int add(int x, int y){
13     return x+y;
14 }
15 //实现x^y
16 int power(int x, int y){
17     int i, c;
18     c=x;
19     for(i=1; i<y; i++){
20         x=x*c;
21     }
22     return x;
23 }
24 //实现求阶乘 n!
25 int fact(int n){
26     int i,z=1;
27     for(i=1;i<=n;i++){
28         z=z*i;
29     }
30     return z;
31 }

结果为：

posted on 2018-03-18 11:25 凯鲁嘎吉阅读(603) 评论(0) 编辑收藏举报