1 /*杭电1.3.6考试排名*/
 2 #include <stdio.h>
 3 #include <string.h>
 4 #include <stdlib.h>
 5 typedef struct person
 6 {
 7     char name[11];
 8     int acnum;   //做对了几题
 9     int timescore;   //时间分-越多越不好
10 }Person;
11 
12 int cmp(const void * a,const void *b)
13 {
14     Person * c=(Person *)a;
15     Person * d=(Person *)b;
16     if (c->acnum!=d->acnum)  //先按ac数
17     {
18         return d->acnum-c->acnum;
19     }
20     else
21     {
22          if (c->timescore!=d->timescore)   //再按时间数
23          {
24              return c->timescore-d->timescore;
25          }
26          else   //名字
27          {
28              return strcmp(c->name,d->name);
29          }
30     }
31 }
32 
33 Person arrperson[100];   //假设最多100人
34 
35 int main(void)
36 {
37     int n,m;
38     int pernum=0;   //记录输入人数
39     int i;
40     scanf("%d %d",&n,&m);
41     while (scanf("%s",arrperson[pernum].name)!=EOF)
42     {
43         int errotime=0,timescore=0,ac=0;   //提交错的次数,时间分(未加错误的罚分),ac题数
44         char chartemp[8];   //装每个数字--用字符串处理
45         char * p;
46         for (i=0;i<n;i++)   //对每题的处理
47         {
48             scanf("%s",chartemp);
49             p=strchr(chartemp,'(');   //在这个字符串中找有没有括号------------------------------------------------------------------
50             if (p)   //不是null,就是有括号
51             {
52                 int shuzi1,shuzi2;    //前为时间,后卫错次数
53                 sscanf(chartemp,"%d(%d)",&shuzi1,&shuzi2);   //从字符串中提取数字--------------------------------------------------
54                 timescore+=shuzi1;
55                 errotime+=shuzi2;
56                 ac++;
57             }
58             else   //是null,就是没有括号----直接得到数字
59             {
60                 int shuzi;
61                 sscanf(chartemp,"%d",&shuzi);
62                 if (shuzi>0)   //数字<=零不管了,都是没有通过
63                 {
64                     timescore+=shuzi;
65                     ac++;
66                 }
67             }
68         }
69         timescore=timescore+errotime*m;
70         arrperson[pernum].timescore=timescore;
71         arrperson[pernum].acnum=ac;
72         pernum++;   //人数加
73     }
74     qsort(arrperson,pernum,sizeof(Person),cmp);
75     for (i=0;i<pernum;i++)
76     {
77         printf("%-10s %2d %4d\n",arrperson[i].name,arrperson[i].acnum,arrperson[i].timescore);
78     }
79     getchar();
80     return 0;
81 }

 

posted on 2013-04-02 20:35  简单的信仰  阅读(230)  评论(0编辑  收藏  举报