描述

定义一个包含图书信息(书号、书名、价格)的顺序表,读入相应的图书数据来完成图书信息表的创建,然后根据指定的待入库的新图书的位置和信息,将新图书插入到图书表中指定的位置上,最后输出新图书入库后所有图书的信息。

输入

总计n+3行。首先输入n+1行,其中,第一行是图书数目n,后n行是n本图书的信息(书号、书名、价格),每本图书信息占一行,书号、书名、价格用空格分隔,价格之后没有空格。其中书号和书名为字符串类型,价格为浮点数类型。之后输入第n+2行,内容仅为一个整数,代表待入库的新图书的位置序号。最后输入第n+3行,内容为新图书的信息,书号、书名、价格用空格分隔。

输出

若插入成功: 输出新图书入库后所有图书的信息(书号、书名、价格),总计n+1行,每行是一本图书的信息,书号、书名、价格用空格分隔。其中价格输出保留两位小数。 若插入失败: 只输出以下提示:抱歉,入库位置非法!

输入样例 1 

7
9787302257646 Data-Structure 35.00
9787302164340 Operating-System 50.00
9787302219972 Software-Engineer 32.00
9787302203513 Database-Principles 36.00
9787810827430 Discrete-Mathematics 36.00
9787302257800 Data-Structure 62.00
9787811234923 Compiler-Principles 62.00
2
9787822234110 The-C-Programming-Language 38.00

输出样例 1

9787302257646 Data-Structure 35.00
9787822234110 The-C-Programming-Language 38.00
9787302164340 Operating-System 50.00
9787302219972 Software-Engineer 32.00
9787302203513 Database-Principles 36.00
9787810827430 Discrete-Mathematics 36.00
9787302257800 Data-Structure 62.00
9787811234923 Compiler-Principles 62.00

输入样例 2 

7
9787302257646 Data-Structure 35.00
9787302164340 Operating-System 50.00
9787302219972 Software-Engineer 32.00
9787302203513 Database-Principles 36.00
9787810827430 Discrete-Mathematics 36.00
9787302257800 Data-Structure 62.00
9787811234923 Compiler-Principles 62.00
9
9787822234110 The-C-Programming-Language 38.00

输出样例 2

Sorry,the position to be inserted is invalid!
#include <iostream>
#include<iomanip>
using namespace std;
#define MAXSIZE 10000

typedef struct 
{
	string no;
	string name;
	double price;
}Book;

typedef struct
{
	Book *elem;
	int num;
}SqList;

void Aver(SqList &L)
{
	double aver=0,sum=0;int i=0;
	for(i=0;i<L.num;i++)
		sum=sum+L.elem[i].price;
	aver=sum/L.num;
	for(i=0;i<L.num;i++)
	{
		if(L.elem[i].price<aver)
			L.elem[i].price=1.2*L.elem[i].price;
		else if(L.elem[i].price>=aver)
			L.elem[i].price=1.1*L.elem[i].price;
	}
	cout<<setiosflags(ios::fixed)<<setprecision(2)<<aver<<endl;
}

void Sort(SqList &L)
{
	int i=0,j=0;
	for(i=0;i<L.num-1;i++)
		for(j=0;j<L.num-1-i;j++)
			if(L.elem[j].price<L.elem[j+1].price)
			{
				Book temp;
				temp=L.elem[j];
				L.elem[j]=L.elem[j+1];
				L.elem[j+1]=temp;
			}
}

void Input(SqList &L)
{
	int n;int i=0;
	cin>>n;
	string a,b;
	double c;
	while(i<n)
	{	
		cin>>a>>b>>c;
		if(i==n) break;
		L.elem[L.num].no=a;
		L.elem[L.num].name=b;
		L.elem[L.num].price=c;
		L.num++;
		i++;
	}
	return ;
}

void Output(SqList &L)
{
	int i;
	for(i=0;i<=L.num-1;i++)
		cout<<L.elem[i].no<<" "<<L.elem[i].name<<" "<<setiosflags(ios::fixed)<<setprecision(2)<<L.elem[i].price<<endl;
	return ;
}

void InitList(SqList &L)
{
	L.elem=new Book[MAXSIZE];
	if(!L.elem) return;
	L.num=0;
	return;
}

void Upsidedown(SqList &L)
{
	int i;
	for(i=0;i<L.num/2;i++)
	{
		Book temp;
		temp=L.elem[i];
		L.elem[i]=L.elem[L.num-1-i];
		L.elem[L.num-1-i]=temp;
	}
		
 } 
 
void mostexpen(SqList &L)
{
	Book max=L.elem[0];
	int flag[MAXSIZE]; 
	int i=0,k=0;
	for(i=0;i<L.num-1;i++)
	{
		if(L.elem[i].price>max.price)
		{
			max=L.elem[i];
		}
	}
	
	for(i=0;i<L.num-1;i++)
	{
		if(L.elem[i].price==max.price)
		{
			flag[k]=i;
			k++;
		}
	}

	cout<<k<<endl;
	for(i=k-1;i>=0;i--)
		cout<<L.elem[flag[i]].no<<" "<<L.elem[flag[i]].name<<" "<<setiosflags(ios::fixed)<<setprecision(2)<<L.elem[flag[i]].price<<endl;
	return ;
}

void favourite(SqList &L)
{
	int n;int i;int j;string fav[10];	int flag[MAXSIZE]; int k=0;
	cin>>n;
	for(i=0;i<n;i++)
	{
		cin>>fav[i];
	}
	
	for(j=0;j<n;j++)
	{
		for(i=0;i<L.num-1;i++)
		{
			if(fav[j]==L.elem[i].name)
			{
					flag[k]=i;
					k++;
			}
		}
		if(k==j)
		cout<<"Sorry,there is no your favourite!"<<endl;
		else
		{
			cout<<k<<endl;
			for(i=0;i<k;i++)
				cout<<L.elem[flag[i]].no<<" "<<L.elem[flag[i]].name<<" "<<setiosflags(ios::fixed)<<setprecision(2)<<L.elem[flag[i]].price<<endl;
		}
		
	}
	
}

void BestLocate(SqList &L)
{
	int n;int i;int j;int no[10]; int k=0;
	cin>>n;
	for(i=0;i<n;i++)
	{
		cin>>no[i];
	}
	
	for(j=0;j<n;j++)
	{
		for(i=0;i<L.num-1;i++)
		{
			if(no[j]==i+1)
			{
				cout<<L.elem[i].no<<" "<<L.elem[i].name<<" "<<setiosflags(ios::fixed)<<setprecision(2)<<L.elem[i].price<<endl;
				k++;
			}
		}
		if(k==j)
		cout<<"Sorry,the book on the best position doesn't exist!"<<endl;
	}
}

void Add(SqList &L)
{
	int no; Book add;int j;
	cin>>no;
	cin>>add.no>>add.name>>add.price;
	if(no>L.num+1||no<1)
	{
		cout<<"Sorry,the position to be inserted is invalid!"<<endl;
		return;
	}
	for(j=L.num-1;j>=no-1;j--)
	{
		L.elem[j+1]=L.elem[j];
	}
	L.elem[no-1]=add;
	L.num++;
	Output(L);
	return;
 } 

int main()
{
	SqList L;
	InitList(L);
	Input(L); 
	Add(L);
	//BestLocate(L);
	//favourite(L); 
	//Upsidedown(L);
	//mostexpen(L);
	//Output(L);
	return 0;
}

附:

>>数据结构实验OJ题库

posted on 2020-02-15 02:13  海月CSDN  阅读(547)  评论(0编辑  收藏  举报