题面:

思路:

 

代码:

#include<bits/stdc++.h>
using namespace std;
long long l,r,ans,x=1,n,f;
int main(){
    freopen("zvrk.in","r",stdin);
    freopen("zvrk.out","w",stdout);
    scanf("%lld%lld",&l,&r);
    l--;
    while(l){
        f=l&1;
        l>>=1;
        ans-=x*(l+f);
        x<<=1;
    }
    x=1;
    while(r){
        f=r&1;
        r>>=1;
        ans+=x*(r+f);
        x<<=1;
    }
    printf("%lld",ans);
    return 0;
}

 

posted on 2018-10-04 14:08  Tolye  阅读(135)  评论(0编辑  收藏  举报