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查询本月所有的天数:

--本月所有的天数
select convert(varchar(10),dateadd(DAY,t2.number,t1.day),120) day from 
(select substring(convert(varchar,GETDATE(),120),1,7)+'-01' day) t1, 
(select number from MASTER..spt_values WHERE TYPE='P' AND number>=0 and number<=31) t2 
where convert(varchar(10),dateadd(DAY,t2.number,t1.day),120) like substring(convert(varchar,GETDATE(),120),1,7)+'%'

 

查询本周所有的天数:

 select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 0),120)
union all select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 1),120)
union all select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 2),120)
union all select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 3),120)
union all select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 4),120)
union all select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 5),120)
union all select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 6),120)


示例:

如下图所示,有表MO_Orders,字段:BookTime,Number,Count,有如下数据。

 

查询出本周的每天的数据总和,语句如下:

 with t as 
( 
    select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 0),120)
    union all select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 1),120)
    union all select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 2),120)
    union all select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 3),120)
    union all select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 4),120)
    union all select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 5),120)
    union all select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 6),120)
)
select id=ROW_NUMBER()OVER(ORDER BY t1.date),
        DATENAME(weekday,t1.date) as weekday,
        t1.date,
        Numbers=sum(isnull(t2.Number,0)),  
        Count=sum(isnull(t2.Count,0)) 
from t t1 
left join
(  
    select substring(convert(varchar,BookTime,120),1,11) as BookTime,
            Number,Count 
    from  MO_Orders 
    where datediff(wk,BookTime-1,getdate()) = 0  
    )
    t2 
on t1.date= substring(convert(varchar,t2.BookTime,120),1,11)
group by t1.date 

 

查询效果如下图,其中 weekday为星期,此图还需替换,稍后补上:

 

示例:如下图所示,有表: MO_Orders,字段:BookTime,Cost,Count 。

查询本月的所有数据总和(其中:total=Cost*Count)。

查询出本月的每天的数据总和,显示每天的,查询语句如下:

 with t as 
( 
  select convert(varchar(10),dateadd(DAY,t2.number,t1.day),120) date from 
    (select substring(convert(varchar,GETDATE(),120),1,7)+'-01' day) t1, 
    (select number from MASTER..spt_values WHERE TYPE='P' AND number>=0 and number<=31) t2 
    where convert(varchar(10),dateadd(DAY,t2.number,t1.day),120) like substring(convert(varchar,GETDATE(),120),1,7)+'%'
)
select id=ROW_NUMBER()OVER(ORDER BY t1.date),
        t1.date,
        CostTotal=sum(isnull(t2.CostTotal,0))
from t t1 
left join 
(    
    select BookTime,sum(CostTotal) as CostTotal from 
    (
        select substring(convert(varchar,BookTime,120),1,11) as BookTime,
                Cost*Count as CostTotal 
        from  MO_Orders 
        where datediff(month,BookTime,getdate()) = 0 
    ) o group by BookTime
) t2
on t1.date= t2.BookTime 
group by t1.date

 

查询结果如下图:

 

posted on 2017-02-17 15:47  永不言弃!  阅读(16117)  评论(1编辑  收藏  举报