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Just treat the Nested List as a tree, and dfs it: private int sum =0; public int depthSum(List<NestedInteger> nestedList) { helper(nestedList, 1); ret
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posted @ 2022-02-08 14:37
阳光明媚的菲越
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The simplest way that I can think to solve this problem is using a PriorityQueue: public int[][] kClosest(int[][] points, int k) { PriorityQueue<int[]
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posted @ 2022-02-08 14:10
阳光明媚的菲越
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For example, if the int[] w ={3,14,1,7}, we can make a presum array based on it: int[] presums = {3, 17, 18, 25} We using Ramdom's nextInt() to genera
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posted @ 2022-02-08 13:46
阳光明媚的菲越
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posted @ 2022-02-08 13:29
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This problem can be solved by using the solution of 236. Lowest Common Ancestor of a Binary Tree. While the tree here is a binary search tree, so the
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posted @ 2022-02-08 09:44
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This problem is just as same as "235. Lowest Common Ancestor of a Binary Search Tree", the only difference is, 235 is two points, 1676 is 1~n points.
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posted @ 2022-02-08 08:55
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The first solution of this problem can be based on the 236. Lowest Common Ancestor of a Binary Tree too: public Node lowestCommonAncestor(Node p, Node
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posted @ 2022-02-08 08:40
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