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78. Subsets List<List<Integer>> res = new ArrayList<>(); public List<List<Integer>> subsets(int[] nums) { backtracking(nums, 0, new ArrayList<>()); re 阅读全文
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My First PriorifyQueue Solution This soltion use a Map to record the frequency of every number, and then use PriorityQueue to sort by frequency. The t 阅读全文
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My First BFS Solution public boolean wordBreak(String s, List<String> wordDict) { if(wordDict.contains(s)) return true; Queue<String> queue = new Link 阅读全文
