I and OI
Past...

AC自动机模板题..

code:

const maxnodes=500000;
var   fx:array[1..8] of char=('E','F','G','H','A','B','C','D');
      t:array[0..maxnodes,'A'..'Z'] of longint;
      f,q,w:array[0..maxnodes] of longint;
      e:array[0..1001,0..1001] of char;
      s:array[0..1001] of char;
      colu,line:array[0..1] of longint;
      done:array[0..1001] of boolean;
      ans:array[0..1001] of record x,y,f:longint; end;
      n,m,num,u,i,j,k,l,r,root,size,x,y,p,li,co,tmp,len:longint;
      c:char;


      function nx(var x,y:longint; f:longint):char;
      begin
            case f of
            1:dec(x);
            2:begin dec(x); inc(y); end;
            3:inc(y);
            4:begin inc(x); inc(y); end;
            5:inc(x);
            6:begin inc(x); dec(y); end;
            7:dec(y);
            8:begin dec(x); dec(y); end;
            end;
            if (x<1)or(x>n)or(y<1)or(y>m) then exit('!');
            exit(e[x,y]);
      end;



begin
      readln(n,m,num);
      line[0]:=1;
      line[1]:=n;
      colu[0]:=1;
      colu[1]:=m;
      for i:=1 to n do
      begin
            for j:=1 to m do read(e[i,j]);
            readln;
      end;

      root:=0;
      size:=0;

      for i:=1 to num do
      begin
            len:=0;
            while not eoln do
            begin
                  inc(len);
                  read(s[len]);
            end;
            p:=root;
            for j:=len downto 1 do
            begin
                  c:=s[j];
                  if t[p][c]=0 then
                  begin
                        inc(size);
                        t[p][c]:=size;
                  end;
                  p:=t[p][c];
            end;
            w[p]:=i;
            readln;
      end;

      l:=0;
      r:=0;
      for c:='A' to 'Z' do
      if t[root][c]<>0 then
      begin
            inc(r);
            q[r]:=t[root][c];
            f[q[r]]:=root;
      end;
      while l<r do
      begin
            inc(l);
            u:=q[l];
            for c:='A' to 'Z' do
            if t[u][c]<>0 then
            begin
                  inc(r);
                  q[r]:=t[u][c];
                  p:=f[u];
                  while (p<>root)and(t[p][c]=0) do p:=f[p];
                  f[q[r]]:=t[p][c];
            end;
      end;

      for k:=1 to 8 do
         for li:=0 to 1 do
            for co:=1 to m do
            begin
                  x:=line[li];
                  y:=co;
                  p:=root;
                  c:=e[x,y];
                  while true do
                  begin
                        while (p<>root)and(t[p][c]=0)do p:=f[p];
                        p:=t[p][c];
                        tmp:=p;
                        while tmp<>root do
                        begin
                              if (w[tmp]>0)and(not done[w[tmp]]) then
                              begin
                                    ans[w[tmp]].x:=x;
                                    ans[w[tmp]].y:=y;
                                    ans[w[tmp]].f:=k;
                                    done[w[tmp]]:=true;
                              end;
                              tmp:=f[tmp];
                        end;
                        c:=nx(x,y,k);
                        if c='!' then break;
                  end;
            end;
      for k:=1 to 8 do
         for co:=0 to 1 do
            for li:=1 to n do
            begin
                  x:=li;
                  y:=colu[co];
                  p:=root;
                  c:=e[x,y];
                  while true do
                  begin
                        while (p<>root)and(t[p][c]=0)do p:=f[p];
                        p:=t[p][c];
                        tmp:=p;
                        while tmp<>root do
                        begin
                              if (w[tmp]>0)and(not done[w[tmp]]) then
                              begin
                                    ans[w[tmp]].x:=x;
                                    ans[w[tmp]].y:=y;
                                    ans[w[tmp]].f:=k;
                                    done[w[tmp]]:=true;
                              end;
                              tmp:=f[tmp];
                        end;
                        c:=nx(x,y,k);
                        if c='!' then break;
                  end;
            end;
      for i:=1 to num do writeln(ans[i].x-1,' ',ans[i].y-1,' ',fx[ans[i].f]);
end.

 

 

 

posted on 2012-01-02 13:07  exponent  阅读(807)  评论(0编辑  收藏  举报