C#使用LINQ操作XML配置文件读取写入数据配置文件config.xml,xml文件如下:

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2 <?xml version="1.0" encoding="utf-8"?>
3 <Soft>
4 <SN RegCode="01234567890"></SN>
5 <LoginConfig SqlServer="." SqlDB="db" UserCode="sa" UserPwd="123">
6 </LoginConfig>
7 </Soft>

读取指定元素指定属性的值:

1 /// <summary>
2 /// 返回XMl文件指定元素的指定属性值
3 /// </summary>
4 /// <param name="xmlElement">指定元素</param>
5 /// <param name="xmlAttribute">指定属性</param>
6 /// <returns></returns>
7 public static string getXmlValue(string xmlElement,string xmlAttribute)
8 {
9 XDocument xmlDoc = XDocument.Load(xmlName);
10 var results = from c in xmlDoc.Descendants(xmlElement)
11 select c;
12 string s = "";
13 foreach (var result in results)
14 {
15 s = result.Attribute(xmlAttribute).Value.ToString();
16 }
17 return s;
18 }

写入指定元素指定属性的值:

1 /// <summary>
2 /// 设置XMl文件指定元素的指定属性的值
3 /// </summary>
4 /// <param name="xmlElement">指定元素</param>
5 /// <param name="xmlAttribute">指定属性</param>
6 /// <param name="xmlValue">指定值</param>
7 public static void setXmlValue(string xmlElement, string xmlAttribute, string xmlValue)
8 {
9 XDocument xmlDoc = XDocument.Load(xmlName);
10 xmlDoc.Element("Soft").Element(xmlElement).Attribute(xmlAttribute).SetValue(xmlValue);
11 xmlDoc.Save(xmlName);
12 }
13 }

posted on 2011-04-17 14:37  dinid  阅读(10821)  评论(2编辑  收藏  举报