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使用Newtonsoft.Json反序列化收到的字串为JObject或其它支持的数据模型,有时错误,提示如下:

Bad JSON escape sequence: \c. Path 'idno', line 5, position 34.

 

甚纳闷之。遂搜索资料,略有小获,其非法分界符所致。合法的分隔符为:

 

以此为依据,对字串做正则替换,问题解决,录代码以记之。

        static void Main(string[] args)
        {
            string s = @"
            {
                ""name"": ""王艳"",
                ""sex"": ""女"",
                ""idno"": ""34*****\c0"",
                ""addr"": ""安徽省"",
                ""telephone"": ""no number"",
                ""thumbnail"": ""e:\docs\person\thumbnail\wy.jpg"",
                ""Age"": 27,
                ""DeptName"": ""姚江\R中心""
            }
            ";

            //\加bfrnt\/'"为合法分隔符,其它不是,替换
            string pattern = @"(\\[^bfrnt\\/'\""])";
            s = Regex.Replace(s, pattern, "\\$1");
            var jo = JsonConvert.DeserializeObject<JObject>(s);
            Console.WriteLine(jo.ToString());

            Console.ReadLine();
        }

结果如图:

 

参考资料:

How to escape special characters in building a JSON string? - Stack Overflow

Bad JSON escape sequence: \l. Path &#39;Transforms[0].Path&#39;, line 3, position 45. · Issue #343 · mmanela/chutzpah

Newtonsoft.Json高级用法 - 焰尾迭 - 博客园

posted on 2018-12-25 10:09  楚人无衣  阅读(2216)  评论(0编辑  收藏  举报