数据库的格式化如下
分别为姓名|密码|电话号码|邮箱|用户类型
admin|admin123.|28812341026|admin@126.com|1
root|admin123.|134456634887|root@126.com|1
Cevin|admin123.|45566778990|Cevin@126.com|0
bob|admin|12345678|bob@126.com|1
# 1、普通用户
# 登陆，注册，修改密码，查看本用户信息
# 2、管理员用户
# 登陆，注册，修改密码，查看本用户信息
# 删除普通虚拟机，添加普通用户信息
# 查看所有的普通用户，按照指定的关键字搜索用户信息
# 提高普通用户的权限
# 3、要求
# 权限用装饰器
# 用户信息，用文件存储
# 4、文件内容
# 用户名|密码|手机号码|邮箱地址|用户类型
代码如下
#Auther Bob
#--*--coding:utf-8--*--
# 1、普通用户
# 登陆，注册，修改密码，查看本用户信息
# 2、管理员用户
# 登陆，注册，修改密码，查看本用户信息
# 删除普通虚拟机，添加普通用户信息
# 查看所有的普通用户，按照指定的关键字搜索用户信息
# 提高普通用户的权限
# 3、要求
# 权限用装饰器
# 用户信息，用文件存储
# 4、文件内容
# 用户名|密码|手机号码|邮箱地址|用户类型
login_dict = {"is_login": None, "login_type": None}
login_list = []
user_list = []
tmpe_user_list = []
with open("db", "r", encoding="utf-8") as f:
for line in f:
tmpe_user_list = line.strip().split("|")
user_list.append(tmpe_user_list[0])
tmpe_user_list = []
def manage_user(func):
def inner(*args, **kwargs):
if login_dict["is_login"] == "1" and login_dict["login_type"] == "1":
ret = func(*args, **kwargs)
return ret
elif login_dict["is_login"] == None:
print("请先登陆")
login()
elif login_dict["is_login"] == "1" and login_dict["login_type"] == None:
print("请使用管理员账号登陆")
login()
else:
pass
return inner
def common_user(func):
def inner(*args, **kwargs):
if login_dict["is_login"] == None:
print("请先登陆")
login()
elif login_dict["is_login"] == "1":
ret = func()
return ret
return inner
def login():
user_name = input("请输入用户名：")
user_passwd = input("请输入%s的密码：" %(user_name))
if user_name in user_list:
with open("db", "r", encoding="utf-8") as f:
for line in f:
login_list = line.strip().split("|")
# print(login_list[0])
# print(login_list[1])
if user_name == login_list[0] and user_passwd == login_list[1]:
print('欢迎%s登陆管理平台' %(user_name))
if login_list[4] == "1":
login_dict["is_login"] = "1"
login_dict["login_type"] = "1"
print(login_dict)
else:
login_dict["is_login"] = "1"
login_dict["login_type"] = None
print(login_dict)
break
else:
print("用户名或者密码错误，请重新登陆:")
login_dict["is_login"] = None
login_dict["login_type"] = None
login()
else:
print("用户名或者密码错误，请重新登陆")
login_dict["is_login"] = None
login_dict["login_type"] = None
login()
@common_user
def regi_common():
break_flag = False
while True:
if break_flag == True:
break
else:
login_name = input("请输入需要注册的用户名：")
if login_name in user_list:
print("该用户名已经存在，请重新输入注册的用户名")
regi_common()
else:
login_paswd = input("请输入%s的用户密码：" % (login_name))
login_number = input("请输入%s的电话号码：" % (login_name))
login_email = input("请输入%s的邮箱地址：" % (login_name))
while True:
if login_dict["is_login"] == "1" and login_dict["login_type"] == "1":
option = input("请输入%s的用户类型\n1：管理员\n2：普通用户\n" % (login_name))
if option == "1":
login_type = "1"
with open("db","a",encoding="utf-8") as f1:
user_info = "\n" + login_name + "|" + login_paswd + "|" + login_number + "|" + login_email + "|" + login_type
f1.write(user_info)
break_flag = True
user_list.append(login_name)
break
elif option == "2":
login_type = "0"
with open("db", "a", encoding="utf-8") as f1:
user_info = "\n" + login_name + "|" + login_paswd + "|" + login_number + "|" + login_email + "|" + login_type
f1.write(user_info)
break_flag = True
user_list.append(login_name)
break
else:
print("无效的输入，请重新输入")
continue
elif login_dict["is_login"] == "1" and login_dict["login_type"] == None:
option = input("请输入%s的用户类型\n1：普通用户\n" % (login_name))
if option == "1":
login_type = "0"
with open("db", "a", encoding="utf-8") as f1:
user_info = "\n" + login_name + "|" + login_paswd + "|" + login_number + "|" + login_email + "|" + login_type
f1.write(user_info)
break_flag = True
user_list.append(login_name)
break
else:
print("无效的输入，请重新输入")
else:
pass
@manage_user
def change_password():
while True:
change_name = input("请输入需要修改密码的欧用户名")
if change_name in user_list:
# old_passwd = input("请输入%s的旧密码" %(change_name))
change_passwd = input("请输入%s的新密码" %(change_name))
with open("db","r",encoding="utf-8") as f1,open("temp","w",encoding="utf-8") as f2:
for line in f1:
change_list = line.strip().split("|")
if change_name == change_list[0]:
new = line.replace(line.strip().split("|")[1],change_passwd)
f2.write(new)
else:
f2.write(line)
change_list = []
with open("temp","r",encoding="utf-8") as f1,open("db","w",encoding="utf-8") as f2:
for line in f1:
f2.write(line)
print("用户%s密码已经修改成功" %(change_name))
break
# break
else:
print("%s不在用户列表中，请重新输入要修改的用户名：" %(change_name))
option = input("是否要继续1：退出；2：继续")
if option == "1":
exit()
elif option == "2":
break
else:
continue
@manage_user
def view_user():
while True:
print(user_list)
view_name_db = str(input("请输入要查询的用户名："))
if view_name_db in user_list:
# print(view_name_db)
with open("db","r",encoding="utf-8") as f1:
for line in f1:
view_list = line.strip().split("|")
if view_name_db == view_list[0]:
if view_list[4] == "1":
view_type = "管理员"
elif view_list[4] == "0":
view_type = "普通用户"
s = "%s的信息如下" %(view_name_db)
print(s.center(100,"-"))
view_info = "用户名：" + view_list[0] + "\n" + "密码：" + view_list[1] + "\n" + "电话号码：" + view_list[2] + "\n" + "邮箱地址：" + view_list[3] + "\n" + "用户类型：" + view_type
print(view_info)
option = input("是否需要继续查询用户名：\n1：是\n2：否")
if option == "1":
continue
elif option == "2":
return True
else:
continue
# view_list = []
else:
print("用户名%s不存在" %(view_name_db))
option = input("是否需要重新查询用户名：\n1：是\n2：否")
if option == 1:
continue
elif option == 2:
break
else:
continue
@manage_user
def del_user():
while True:
del_name = input("请输入需要删除的用户")
if del_name not in user_list:
option = input("用户名%s不存在，是否需要重新删除用户名：\n1：是\n2：否" %(del_name))
if option == "1":
continue
elif option == "2":
break
else:
continue
else:
with open("db","r",encoding="utf-8") as f1,open("temp","w",encoding="utf-8") as f2:
for line in f1:
if line.strip().startswith(del_name):
continue
else:
f2.write(line)
with open("temp","r",encoding="utf-8") as f1,open("db","w",encoding="utf-8") as f2:
for line in f1:
f2.write(line)
print("用户名%s已经删除成功" %(del_name))
user_list.remove(del_name)
while True:
option = input("是否需要继续删除用户：\n1：是\n2：否")
if option == "1":
break
elif option == "2":
return True
else:
print("无效的输入，请重新输入")
def main():
while True:
s = "请输入你要做什么"
print(s.center(100,"-"))
option = input("1、登陆\n2、查看用户\n3、删除用户\n4、修改密码\n5、注册用户")
if option == "1":
login()
elif option == "2":
view_user()
elif option == "3":
del_user()
elif option == "4":
change_password()
elif option == "5":
regi_common()
else:
while True:
option = input("无效的输入，是否需要继续：\n1、退出\n2、继续\n")
if option == "1":
exit()
elif option == "2":
break
else:
continue
main()
