Hi_Amos
坚持每天都在进步!!
    @Test
    public void test33() {
        String phoneString = "哈哈,13888889999";
        // 提取数字
        // 1
        Pattern pattern = Pattern.compile("[^0-9]");
        Matcher matcher = pattern.matcher(phoneString);
        String all = matcher.replaceAll("");
        System.out.println("phone:" + all);
        // 2
        Pattern.compile("[^0-9]").matcher(phoneString).replaceAll("");
    }
@Test
    public void test() {
        // 提取张三 去除数字
        String r_name3 = "张三 13599998888 000000";
        Pattern pattern = Pattern.compile("[\\d]");
        Matcher matcher = pattern.matcher(r_name3);
        System.out.println(matcher.replaceAll("").trim());
    }

 

需求:过滤除点号外的所有非数字:

        String abc = "价格:0.00元";
        Pattern compile = Pattern.compile("\\d+\\.\\d+");
        Matcher matcher = compile.matcher(abc);
        matcher.find();
        String string = matcher.group();//提取匹配到的结果
        System.out.println(string);//0.00        

 

需求:只要提取数字其它都不需要

String abc = "手机:1319999999";    
System.out.println(abc.replaceAll("\\D", ""));//1319999999

 

 需求:提取价格出来

package com.infomorrow.parser_datasource;

import java.util.regex.Matcher;
import java.util.regex.Pattern;

import org.junit.Test;

public class test_money {
    @Test
    public void test(){
        //0
        //0.1
        //24.13
        String moneyString="1";
        Double extract_cost = extract_cost_dot(moneyString);
        System.out.println("extract_cost:"+extract_cost);
    }
    /**
     * 提取金额,规则为只提取数字和点号,必须有点号
     * 格式可以为0.0或者,11
     * @param cost
     * @return
     */
    public   Double extract_cost_dot(String cost) {
        Pattern compile = Pattern.compile("(\\d+\\.\\d+)|(\\d+)");
        Matcher matcher = compile.matcher(cost);
        matcher.find();
        return Double.valueOf(matcher.group());
    }
}

 

 

 

 

 

posted on 2013-11-22 11:30  Hi_Amos  阅读(38213)  评论(0编辑  收藏  举报