Shirlies
宁静专注认真的程序媛~
代码如下:
 1 #include <cstdio>
 2 #include <cmath>
 3 #include <algorithm>
 4 
 5 void solve();
 6 int  L,sx,sy,px,py;
 7 
 8 int main()
 9 {
10     while(scanf("%d",&L),L)
11     {
12         scanf("%d%d%d%d",&sx,&sy,&px,&py);
13 
14         if(py > L || px > L || py < -L || px < -L)
15         {
16             printf("Out Of Range\n");
17             continue;
18         }
19 
20         solve();
21     }
22 
23     return 0;
24 }
25 
26 void solve()
27 {
28     int a = px - sx;
29     int b = py - sy;
30 
31     if(a == 0)
32     {
33         if(abs(b) <= 1)
34         {
35             printf("Yes\n");
36         }
37         else
38         {
39             printf("No\n");
40         }
41 
42         return;
43     }
44 
45     if(b == 0)
46     {
47         if(abs(a) <= 1)
48         {
49             printf("Yes\n");
50         }
51         else
52         {
53             printf("No\n");
54         }
55 
56         return;
57     }
58 
59     if(abs(a) == 1 && abs(b) == 1)
60     {
61         printf("Yes\n");
62         return;
63     }
64 
65     int minn = std::min(sx,px);
66     int maxm = std::max(sx,px);
67 
68     for(int i = minn +  1;i < maxm;i ++)
69     {
70         int temp = b * i + a * sy - b * sx;
71         if(temp % a == 0)
72         {
73             if(temp / a < std::max(sy,py) && temp / a > std::min(sy,py))
74             {
75             printf("No\n");
76             return;
77             }
78         }
79     }
80 
81     printf("Yes\n");
82 }

 

posted on 2012-05-20 21:44  Shirlies  阅读(310)  评论(0编辑  收藏  举报