我们在工作中,有时候会需要将字符串转化为16进制字符串给用户,因为ASCII中有些字符,当我们使用printf("%s",p_ch);输出时会杂乱无章,如果采用16进制,会好很多。
因此编写程序,代码如下:
#include <stdio.h> #include <string.h> int strToHex(char *ch, char *hex); int hexToStr(char *hex, char *ch); int hexCharToValue(const char ch); char valueToHexCh(const int value); int main(int argc, char *argv[]) { char ch[1024]; char hex[1024]; char result[1024]; char *p_ch = ch; char *p_hex = hex; char *p_result = result; printf("please input the string:"); scanf("%s",p_ch); strToHex(p_ch,p_hex); printf("the hex is:%s\n",p_hex); hexToStr(p_hex, p_result); printf("the string is:%s\n", p_result); return 0; } int strToHex(char *ch, char *hex) { int high,low; int tmp = 0; if(ch == NULL || hex == NULL){ return -1; } if(strlen(ch) == 0){ return -2; } while(*ch){ tmp = (int)*ch; high = tmp >> 4; low = tmp & 15; *hex++ = valueToHexCh(high); //先写高字节 *hex++ = valueToHexCh(low); //其次写低字节 ch++; } *hex = '\0'; return 0; } int hexToStr(char *hex, char *ch) { int high,low; int tmp = 0; if(hex == NULL || ch == NULL){ return -1; } if(strlen(hex) %2 == 1){ return -2; } while(*hex){ high = hexCharToValue(*hex); if(high < 0){ *ch = '\0'; return -3; } hex++; //指针移动到下一个字符上 low = hexCharToValue(*hex); if(low < 0){ *ch = '\0'; return -3; } tmp = (high << 4) + low; *ch++ = (char)tmp; hex++; } *ch = '\0'; return 0; } int hexCharToValue(const char ch){ int result = 0; //获取16进制的高字节位数据 if(ch >= '0' && ch <= '9'){ result = (int)(ch - '0'); } else if(ch >= 'a' && ch <= 'z'){ result = (int)(ch - 'a') + 10; } else if(ch >= 'A' && ch <= 'Z'){ result = (int)(ch - 'A') + 10; } else{ result = -1; } return result; } char valueToHexCh(const int value) { char result = '\0'; if(value >= 0 && value <= 9){ result = (char)(value + 48); //48为ascii编码的‘0’字符编码值 } else if(value >= 10 && value <= 15){ result = (char)(value - 10 + 65); //减去10则找出其在16进制的偏移量,65为ascii的'A'的字符编码值 } else{ ; } return result; }