Jan 12 - Valid Anagram; Hash Table; Sort; Alphabets; String;

创建两个数组存储字母的个数，再对比两个数组是否相同

代码：

public class Solution {
    public boolean isAnagram(String s, String t) {
        int[] alphabets1 = new int[26];
        int[] alphabets2 = new int[26];
        if(s.length() != t.length()) return false;
        for(int i = 0; i < s.length(); i++){
            alphabets1[(int) (s.charAt(i)-'a')]++;
        }
        for(int i = 0; i < t.length(); i++){
            alphabets2[(int) (t.charAt(i)-'a')]++;
        }
        for(int i = 0; i < 26; i++){
            if(alphabets1[i] != alphabets2[i]) return false;
        }
        return true;
    }
}