#1. 使用while循环输出1 2 3 4 5 6 8 9 10
n = 1
while n <= 10:
    if n == 7:
        pass
    else:
        print(n)
    n = n + 1

#2. 求1 ~100所有数的和

n = 1
count = 0
while n <= 100:
    count = count + n
    n = n + 1
print(count)

# 3. 输出 1~100 内的所有奇数

n = 1
while n < 100:
    if n % 2 != 0:
        print(n)
    else:
        pass
    n = n + 1

# 4. 输出1~100以内的所有偶数

n = 1
while n < 100 :
    if n % 2 == 0:
        print(n)
    else :
        pass
    n = n + 1

#5. 求1-2+3-4+5-6...99的所有数的和

n = 1
count = 0
while n <= 99:
    if n % 2 != 0:
        count = count + n
    else:
        count = count - n
    n = n + 1
print(count)

 while 循环补充:

(1)while ...::

   ...

else :

(2)continue 跳出本次循环,终止当前循环,开始下次循环

(3)break  跳出所有循环

break语句
count = 0
while count < 10 :
    count = count + 1
    print(count)
    break
    print("11111111111111")
print("end")

——》
1
end


continue语句
count = 0
while count < 10 :
    count = count + 1
    print(count)
    continue
    print("11111111111111")
print("end")

——》
1
2
3
4
5
6
7
8
9
10
end

 

posted on 2019-03-14 23:06  晓娇  阅读(184)  评论(0编辑  收藏  举报