58. Length of Last Word

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example,
Given s = "Hello World",
return 5.

自己写的~~

 1 class Solution(object):
 2     def lengthOfLastWord(self, s):
 3         """
 4         :type s: str
 5         :rtype: int
 6         """
 7         if s=='':
 8             return 0
 9             
10         mylist = s.split(' ')
11         for i in mylist[::-1]:
12             if i != '':
13                 return len(i)
14         return 0

1 class Solution(object):
2     def lengthOfLastWord(self, s):
3         """
4         :type s: str
5         :rtype: int
6         """
7         return len(s.strip().split(' ')[-1])

s.strip()删除字符串开头和结尾的空格

s.strip(rm) 删除s字符串中开头、结尾处，位于 rm删除序列的字符

s.lstrip(rm) 删除s字符串中开头处，位于 rm删除序列的字符

s.rstrip(rm) 删除s字符串中结尾处，位于 rm删除序列的字符

posted on 2017-03-14 15:16 Ci_pea 阅读(128) 评论(0) 编辑收藏举报