Given an array and a value, remove all instances of that value in place and return the new length.

Do not allocate extra space for another array, you must do this in place with constant memory.

The order of elements can be changed. It doesn't matter what you leave beyond the new length.

 

 1 class Solution(object):
 2     def removeElement(self, nums, val):
 3         """
 4         :type nums: List[int]
 5         :type val: int
 6         :rtype: int
 7         """
 8         start, end = 0, len(nums) - 1
 9         while start <= end:
10             if nums[start] == val:
11                 nums[start], nums[end], end = nums[end], nums[start], end - 1
12             else:
13                 start +=1
14         return start

将不用的放到最后

 1 class Solution(object):
 2     def removeElement(self, nums, val):
 3         """
 4         :type nums: List[int]
 5         :type val: int
 6         :rtype: int
 7         """
 8         for i in nums[:]:
 9             if i == val:
10                 nums.remove(val)
11         return len(nums)

nums 和 nums[:] 的区别??

posted on 2017-03-13 09:49  Ci_pea  阅读(113)  评论(0编辑  收藏  举报