Stamps

Given a set of N stamp values (e.g., {1 cent, 3 cents}) and an upper limit K to the number of stamps that can fit on an envelope, calculate the largest unbroken list of postages from 1 cent to M cents that can be created.

For example, consider stamps whose values are limited to 1 cent and 3 cents; you can use at most 5 stamps. It's easy to see how to assemble postage of 1 through 5 cents (just use that many 1 cent stamps), and successive values aren't much harder:

  • 6 = 3 + 3
  • 7 = 3 + 3 + 1
  • 8 = 3 + 3 + 1 + 1
  • 9 = 3 + 3 + 3
  • 10 = 3 + 3 + 3 + 1
  • 11 = 3 + 3 + 3 + 1 + 1
  • 12 = 3 + 3 + 3 + 3
  • 13 = 3 + 3 + 3 + 3 + 1.

However, there is no way to make 14 cents of postage with 5 or fewer stamps of value 1 and 3 cents. Thus, for this set of two stamp values and a limit of K=5, the answer is M=13.

The most difficult test case for this problem has a time limit of 3 seconds.

PROGRAM NAME: stamps

INPUT FORMAT

Line 1: Two integers K and N. K (1 <= K <= 200) is the total number of stamps that can be used. N (1 <= N <= 50) is the number of stamp values.
Lines 2..end: N integers, 15 per line, listing all of the N stamp values, each of which will be at most 10000.

SAMPLE INPUT (file stamps.in)

5 2
1 3

OUTPUT FORMAT

Line 1: One integer, the number of contiguous postage values starting at 1 cent that can be formed using no more than K stamps from the set.

SAMPLE OUTPUT (file stamps.out)

13

思路:尝试过很多方法,虽然知道是DP,发现其他方法都有漏洞。没啥可说的。
Executing...
   Test 1: TEST OK [0.000 secs, 11040 KB]
   Test 2: TEST OK [0.000 secs, 11040 KB]
   Test 3: TEST OK [0.000 secs, 11040 KB]
   Test 4: TEST OK [0.000 secs, 11040 KB]
   Test 5: TEST OK [0.000 secs, 11040 KB]
   Test 6: TEST OK [0.000 secs, 11040 KB]
   Test 7: TEST OK [0.000 secs, 11040 KB]
   Test 8: TEST OK [0.000 secs, 11040 KB]
   Test 9: TEST OK [0.000 secs, 11040 KB]
   Test 10: TEST OK [0.054 secs, 11040 KB]
   Test 11: TEST OK [0.518 secs, 11040 KB]
   Test 12: TEST OK [0.119 secs, 11040 KB]
   Test 13: TEST OK [0.000 secs, 11040 KB]

All tests OK.
 1 /*
 2 ID:wuhuaju2
 3 PROG:stamps
 4 LANG:C++
 5 */
 6 #include <cstdio>
 7 #include <iostream>
 8 #include <cstdlib>
 9 #include <algorithm>
10 #include <cstring>
11 #include <string>
12 using namespace std;
13 
14 const int maxn=2000100;
15 int f[maxn];
16 int a[52];
17 int n,k,maxx;
18 
19 void close()
20 {
21     fclose(stdin);
22     fclose(stdout);
23     exit(0);
24 }
25 
26 void work()
27 {
28 }
29 
30 void init ()
31 {
32 freopen("stamps.in","r",stdin);
33 freopen("stamps.out","w",stdout);
34    scanf("%d %d",&k,&n);
35     for (int i=0;i<n;i++)
36         scanf("%d",&a[i]);
37     sort(a,a+n);
38     maxx=a[n-1]*k;
39     for (int i=1;i<=maxx;i++)
40     {
41         f[i]=100000000;
42         for (int j=0;j<n;j++)
43         {
44             if (i-a[j]>=0) //注意:此时是排好序了的!
45                 f[i]=min(f[i],f[i-a[j]]+1);
46             else break; //所以可以break了!
47         }
48     }
49     for (int i=1;i<=maxx;i++)
50         if (f[i]>k)
51         {
52             cout<<i-1<<endl;
53             close();
54         }
55     cout<<maxx<<endl;//这句话比较关键
56 }
57 
58 int main ()
59 {
60     init();
61     work();
62     close();
63     return 0;
64 }


posted on 2013-02-10 12:18  cssystem  阅读(258)  评论(0编辑  收藏  举报