day30 打卡332. 重新安排行程 51. N 皇后 37. 解数独
day30 打卡332. 重新安排行程 51. N 皇后 37. 解数独
332. 重新安排行程
去b站搜了视频讲解在写的。视频地址
class Solution {
List<String> result = new ArrayList<>();
public List<String> findItinerary(List<List<String>> tickets) {
// from to
Map<String, TreeMap<String, Integer>> map = new HashMap<>();
for (List<String> list: tickets) {
String from = list.get(0);
String to = list.get(1);
map.putIfAbsent(from, new TreeMap<String, Integer>());
TreeMap<String, Integer> treeMap = map.get(from);
// 记住to的后面的机票往哪里去飞
treeMap.put(to, treeMap.getOrDefault(to, 0) + 1);
}
// 初始化JFK
result.add("JFK");
backtracking(tickets, map, 0);
return result;
}
private boolean backtracking(List<List<String>> tickets, Map<String, TreeMap<String, Integer>> map, int progress) {
// 机票用完了
if (progress == tickets.size()) {
return true;
}
// 得到 每一次的开始点
String from = result.get(result.size()-1);
// 得到 从开始点可以到达的目标
TreeMap<String, Integer> tos = map.get(from);
if (tos == null || tos.isEmpty() || tos.size() == 0) {
return false;
}
for (String key: tos.keySet()) {
// 没票了
if (tos.get(key) == 0) {
continue;
}
result.add(key);
tos.put(key, tos.get(key) - 1);
if (backtracking(tickets, map, progress+1)) {
return true;
}
result.remove(result.size()-1);
tos.put(key, tos.get(key) + 1);
}
return false;
}
}
51. N 皇后
class Solution {
List<List<String>> result = new ArrayList<>();
public List<List<String>> solveNQueens(int n) {
if (n == 1) {
result.add(Arrays.asList("Q"));
return result;
}
char[][] chessboard = new char[n][n];
for (char[] c: chessboard) {
Arrays.fill(c, '.');
}
backtracking(chessboard, n, 0);
return result;
}
private void backtracking(char[][] chessboard, int n, int row) {
if (row == n) {
// 收获结果,将chessboard转化成list
result.add(getPath(chessboard));
return;
}
for (int i = 0 ; i<n ; i++) {
if (isValid(chessboard, n, row, i)) {
// 符合要求
chessboard[row][i] = 'Q';
backtracking(chessboard, n, row+1);
chessboard[row][i] = '.';
}
}
}
private List<String> getPath(char[][] chessboard) {
List<String> list = new ArrayList<>();
for (char[] c: chessboard) {
list.add(String.copyValueOf(c));
}
return list;
}
private boolean isValid(char[][] chessboard, int n, int row, int col) {
// 检查列
for (int i=0; i<row; ++i) { // 相当于剪枝
if (chessboard[i][col] == 'Q') {
return false;
}
}
// 检查45度对角线
for (int i=row-1, j=col-1; i>=0 && j>=0; i--, j--) {
if (chessboard[i][j] == 'Q') {
return false;
}
}
// 检查135度对角线
for (int i=row-1, j=col+1; i>=0 && j<=n-1; i--, j++) {
if (chessboard[i][j] == 'Q') {
return false;
}
}
return true;
}
}
37. 解数独
class Solution {
public void solveSudoku(char[][] board) {
backtracking(board);
}
private boolean backtracking(char[][] board) {
int n = board.length;
for (int i = 0 ; i<n ; i++) {
for (int j = 0 ; j<n ; j++) {
if (board[i][j] == '.') {
// 放数字
for (char k = '1'; k<='9' ; k++) {
if (isValid(board, i, j, k)) {
// 如果符合要求,进行回溯
board[i][j] = k;
boolean result = backtracking(board);
if (result) return true;
board[i][j] = '.';
}
}
// 如果9个数字都不行,返回false
return false;
}
}
}
return true;
}
private boolean isValid(char[][] board, int row, int col, char val) {
// 判断一行是否有等于val
for (int i = 0 ;i<board.length ; i++) {
if (board[row][i] == val) return false;
}
// 判断一列是否有等于val
for (int i = 0 ;i<board.length ; i++) {
if (board[i][col] == val) return false;
}
// 判断所在九宫格是否有等于val
int startX = (row / 3) * 3;
int startY = (col / 3) * 3;
for (int i = startX ; i < startX+3 ; i++) {
for (int j = startY ; j < startY+3 ; j++) {
if (board[i][j] == val) return false;
}
}
return true;
}
}
参考资料
分类:
LeetCode
【推荐】国内首个AI IDE,深度理解中文开发场景,立即下载体验Trae
【推荐】编程新体验,更懂你的AI,立即体验豆包MarsCode编程助手
【推荐】抖音旗下AI助手豆包,你的智能百科全书,全免费不限次数
【推荐】轻量又高性能的 SSH 工具 IShell:AI 加持,快人一步
· TypeScript + Deepseek 打造卜卦网站:技术与玄学的结合
· Manus的开源复刻OpenManus初探
· AI 智能体引爆开源社区「GitHub 热点速览」
· 三行代码完成国际化适配,妙~啊~
· .NET Core 中如何实现缓存的预热?