ajax php POST 提交例子
<!DOCTYPE html PUBLIC "-//W
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=gb2312" />
<title>利用XMLHTTP无刷新添加数据</title>
<script type="text/javascript">
<!--
function AddDatapost(sUserId,sUserName)
{
var objxmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
//sUserId=escape(sUserId);
//sUserName=escape(sUserName);
var userinfo="userid="+sUserId+"&username="+sUserName;
objxmlhttp.open("Post","ajax_output.php",false);
//需要定义发送的头
objxmlhttp.setRequestHeader("Content-Length",userinfo.length)
objxmlhttp.setRequestHeader("Content-Type","application/x-www-form-urlencoded")
objxmlhttp.send(userinfo)
//清空输入数据
document.all.userid.value="";
document.all.username.value="";
alert(objxmlhttp.responseText);
document.getElementById("xxxx").innerHTML= objxmlhttp.responseText;
}
//-->
</script>
</head>
<body>
<input type="text" name="userid"><br>
<input type="text" name="username"><br>
<input type="button" onclick="AddDatapost(document.all.userid.value,document.all.username.value)" value="AdddData">
</body>
</html>
<?
echo $_POST['userid'];
echo $_POST['username'];
?>
<script language="javascript">
var xmlHttp;
function sendCall(url, params) {
if (window.ActiveXObject) {
xmlHttp = new ActiveXObject("Microsoft.XMLHTTP");
} else if (window.XMLHttpRequest) {
xmlHttp = new XMLHttpRequest();
}
xmlHttp.onreadystatechange = callBack;
xmlHttp.open('POST', url, true);
xmlHttp.setrequestheader("content-length",params.length);
xmlHttp.setRequestHeader('Content-Type', 'application/x-www-form-urlencoded');
xmlHttp.setRequestHeader("Connection", "close");
xmlHttp.send(params);
}
function callBack() {
if (xmlHttp.readyState == 4) {
if (xmlHttp.status == 200) {
document.getElementById("title").innerHTML = xmlHttp.responseText ;
}
}
}
function submitMsgForm(){
var receiver = document.getElementById("receiver").value;
var title = document.getElementById("title").value;
var content = document.getElementById("content").value;
var params = "receiver="+receiver+"&title="+title+"&content="+content;
var url = "ajax_output.php";
sendCall(url, params);
}
</script>
<form name="form" action="" method="post">
<div id="xxxx"></div>
<TABLE>
<TR>
<TD>receiver</TD>
<TD><INPUT TYPE="text" NAME="receiver" id="receiver" ></TD>
</TR>
<TR>
<TD>title</TD>
<TD><INPUT TYPE="text" NAME="title" id="title" ></TD>
</TR>
<TR>
<TD>content</TD>
<TD><INPUT TYPE="text" NAME="content" id="content" ></TD>
</TR>
<TR>
<TD></TD>
<TD><INPUT TYPE="button" name="submit" value="submit" onclick="submitMsgForm()"></TD>
</TR>
</TABLE>
</form>
<?
$receiver = $_POST['receiver'];
$title = $_POST['title'];
$content =$_POST['content'];
$content = $receiver . $title . $content;
echo $content;
?>
