摘要: //int型 inline int read(){ int s=0;char ch=getchar(); while(ch<'0'||ch>'9') ch=getchar(); while(ch>='0'&&ch<='9') {s=s*10+ch-'0';ch=getchar();} return 阅读全文
posted @ 2017-04-18 19:28 *zzq 阅读(187) 评论(0) 推荐(0) 编辑
摘要: Rank Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1622 Accepted Submission(s): 625 Problem Des 阅读全文
posted @ 2017-04-18 18:28 *zzq 阅读(267) 评论(0) 推荐(0) 编辑