数据转换-16进制字符

任务详情

  1. 在openEuler(推荐)或Ubuntu或Windows(不推荐)中完成下面任务

  2. 在utils.h和utils.c中完成16进制字符'0'-'9','A'-'F','a'-'f'与十六进制数据0-15的转换功能(10’):

int Hex2Char(unsigned int fromi,unsigned char * toc);
int Char2Hex(unsigned char fromc,unsigned int * toi);
  1. 并写出测试代码测试上述函数(不能与下面代码一样),比如:(10’)
unsigned char * c;
Hex2Char(1, &c)
//结果:c = '1'
Hex2Char(15, &c)
//结果:c = 'F'
unsigned int i;
Char2Hex('1', &i);
//结果:i = 1
Char2Hex('F', &i);
//结果:i = 15
  1. 提交代码(或代码链接)和运行结果

任务过程

utils.h

#ifndef _UTIL_H_
#define _UTIL_H_

//char Hex2Char(int i);
//int Char2Hex(char c);

int Hex2Char(int fromi,char * toc);
int Char2Hex(char fromc,int * toi);

int Bitstr2ByteArr(char * bs,char * ba);
int ByteArr2Bitstr(char * ba,char * bs);

int Int2ByteArr(int i,char * ba);
int ByteArr2Int(char * ba,int * i);

#endif

utils.c

#include<stdio.h>
#include"utils.h"
char Hstr = {'0','1','2','3','4','5','6','7','8','9','A','B','C','D','E','F'};

int Hex2Char(int fromi,char *toc)
{
    if(fromi>=0&&fromi<=9)
    {
            *toc= fromi+'0';
    }
    else if(fromi>=10&&fromi<=15)
    {
            *toc = fromi+'A'-10;
    }
    else
    {
        printf("error");
     }
    return 0;
}
int Char2Hex(char fromc,int *toi)
{
        if(fromc>='0'&& fromc<='9')
        {
             *toi= fromc-'0';
        }
        else if(fromc>='A'&& fromc<='F')
        {
             *toi= fromc-'A'+10;

        }
        else
        {
            printf("error");
        }
        return 0;
}

main.c

#include<stdio.h>
#include"utils.h"
int main(){
  int n1,n2;
  char c1,c2;
  printf("请输入一个0~15的数:");
  scanf("%d",&n1);
  Hex2Char(n1,&c1);
  printf("对应的16进制字符是%c\n",c1);
  printf("请输入一个16进制字符:");
  scanf("%c",&c2);
  Char2Hex(c2,&n2);
  printf("对应的数是%d\n",n2);
}

运行结果:

posted @ 2022-05-12 15:15  20191223张俊怡  阅读(160)  评论(0编辑  收藏  举报