P1618 三连击（升级版）

P1618 三连击（升级版）

题目链接：https://www.luogu.org/problem/P1618

思路：

​ 判断三个数的每一位加起来是否等于从1加到9，且每一位相乘是否等于从1乘到9；

代码：

#include <bits/stdc++.h>
using namespace std;

int main()
{
    //freopen("in.txt","r",stdin);
    //freopen("out.txt","w",stdout);
    int a,b,c,max,b1,c1,t1,t2,t3,i,t=0,l;
    cin>>a>>b>>c;
    if(c%a==0&&a!=1&&b%a==0){   //判断是否出现例如2：4：6的情况；
        l = a;
        a = a/l;
        b = b/l;
        c = c/l;
    }
    max = c;
    if(a>=123){         //判读是否出现例如123：456：789的情况；//注意！！！！！！
            t1 = a/10;
            t2 = b/10;
            t3 = c/10;
        if(t1/10+t1%10+a%10+t2/10+t2%10+b%10+t3/10+t3%10+c%10==45&&(t1/10)*(t1%10)*(a%10)*(t2/10)*(t2%10)*(b%10)*(t3/10)*(t3%10)*(c%10)==(1*2*3*4*5*6*7*8*9)){
                cout<<a<<" "<<b<<" "<<c<<endl;
                t = 1;
            }
    }else{
        for(i=123;i<=999/max;i++){
        if(i%a==0){
            b1 = (i/a)*b;
            c1 = (i/a)*c;
            t1 = i/10;
            t2 = b1/10;
            t3 = c1/10;
            if(t1/10+t1%10+i%10+t2/10+t2%10+b1%10+t3/10+t3%10+c1%10==45&&(t1/10)*(t1%10)*(i%10)*(t2/10)*(t2%10)*(b1%10)*(t3/10)*(t3%10)*(c1%10)==(1*2*3*4*5*6*7*8*9)){
                cout<<i<<" "<<b1<<" "<<c1<<endl;
                t = 1;
            }
        }
    }
    }
    if(t==0){
        cout<<"No!!!"<<endl;
    }
    return 0;
}