摘要: 对每个n,答案就是(phi[2]+phi[3]+...+phi[n])*2+1,简单的欧拉函数应用。#include#include#include#include#include#include#include#include#include#include#include#include#inc... 阅读全文
posted @ 2015-03-30 20:03 周洋 阅读(283) 评论(0) 推荐(0) 编辑