jquery中$.ajax的$.get与$.post使用

  <script type='text/javascript' src='http://ajax.useso.com/ajax/libs/jquery/1.7.2/jquery.min.js?ver=3.4.2'></script>
  <script type="text/javascript">
  $(function(){
      var bd=$("form")[0];
      $(bd).submit(function(){
                    
          var cc="addr="+$("#uaddr").val()+"&name="+$("#uname").val();
          $.post("4.php",cc,function(msg){alert(msg.addr+"----"+msg.name)},'json');
                    return false;
          });
      });
  
  </script>
<form action="4.php"><br>
<input name="uname" type="text" id="uname"><br>
<input name="uaddr" type="text" id="uaddr">
<input type="submit" value="提交"></form>

<script type='text/javascript' src='http://ajax.useso.com/ajax/libs/jquery/1.7.2/jquery.min.js?ver=3.4.2'></script>
  <script type="text/javascript">
  $(function(){
      var bd=$("form")[0];
      $(bd).submit(function(){                    
          $.ajax({
              url:'4.php',
              data:{addr:$("#uaddr").val(),name:$("#uname").val()},
              dataType:"json",
              type:'POST',
              success: function(msg){
                  //msg是服务器返回信息
                  alert(msg.addr+"----"+msg.name)
                  }
              });
              return false;
          });
      });
  
  </script>
<form action="4.php"><br>
<input name="uname" type="text" id="uname"><br>
<input name="uaddr" type="text" id="uaddr">
<input type="submit" value="提交"></form>

<?php
$arr=array();
$arr["addr"]=$_POST["addr"];
$arr["name"]=$_POST["name"];
echo json_encode($arr);
?>