简单dfs--回溯
摘要:#题目:输入n,讨论能组成n位数多少种? ###思路:采用dfs,原理递归 void dfs(int u) { if(u == n) { for(int i = 0; i < n; i++)cout << path[i] << " ";//每次输出一层 cout << endl; return; }
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posted @ 2021-07-06 19:43
posted @ 2021-07-06 19:43
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posted @ 2021-02-28 15:15