2023年8月3日
delegate open and send for XMLHttpRequest by rewrite the prototype
摘要： var sendProxied = window.XMLHttpRequest.prototype.send; window.XMLHttpRequest.prototype.send = function() {var object = {}; let data = arguments[0] if 阅读全文
posted @ 2023-08-03 21:28 zyip 阅读(10) 评论(0) 推荐(0) 编辑