使用JS实现图片翻转效果

.flip-container {
perspective:1000px;/*设置假定人眼到投影平面的距离为1000px,只影响3D元素,不影响2D元素*/
width: 1300px;
margin:0 auto;
}
.front,.back {
width:400px;
height:400px;
}
.flipper {
width: 400px;
height: 400px;
border-radius: 50%;
margin-left:10px;
margin-bottom:120px;
display: inline-block;/*div横排显示,变成行级元素*/
transition:0.6s;
transform-style:preserve-3d;
}
.front,.back {
width: 400px;
height: 400px;
border-radius: 20%;
display: inline-block;
}
.back {
display: none;/*隐藏背面*/
}
</style>
</head>
<body>
<div class="flip-container">
<div class="flipper">
<div class="front" style="background:url(imges/4.jpg) no-repeat" ">
<!-- <p>正面</p> -->
</div>
<div class="back" style="background:url(imges/1.gif) no-repeat">
<!-- <p>背面</p> -->
</div>
</div>
<div class="flipper">
<div class="front" style="background:url(imges/4.jpg) no-repeat" ">
<!-- <p>正面</p> -->
</div>
<div class="back" style="background:url(imges/2.gif) no-repeat">
<!-- <p>背面</p> -->
</div>
</div>
<div class="flipper">
<div class="front" style="background:url(imges/4.jpg) no-repeat" ">
<!-- <p>正面</p> -->
</div>
<div class="back" style="background:url(imges/3.gif) no-repeat">
<!-- <p>背面</p> -->
</div>
</div>
<div class="flipper">
<div class="front" style="background:url(imges/4.jpg) no-repeat" ">
<!-- <p>正面</p> -->
</div>
<div class="back" style="background:url(imges/4.gif) no-repeat">
<!-- <p>背面</p> -->
</div>
</div>
<div class="flipper">
<div class="front" style="background:url(imges/4.jpg) no-repeat" ">
<!-- <p>正面</p> -->
</div>
<div class="back" style="background:url(imges/5.gif) no-repeat">
<!-- <p>背面</p> -->
</div>
</div>
<div class="flipper">
<div class="front" style="background:url(imges/4.jpg) no-repeat" ">
<!-- <p>正面</p> -->
</div>
<div class="back" style="background:url(imges/6.gif) no-repeat">
<!-- <p>背面</p> -->
</div>
</div>
</div>
<script>
$(function(){
$(".flipper").hover(function(){ //鼠标移动的function
$(this).css("transform","rotateY(180deg)");//鼠标移上去旋转180度
var n=$(this).index(); //找到鼠标经过的flipper
$(".back").eq(n).css("display","inline-block"); //让back显示出来
$(".front").eq(n).hide(); //隐藏front
},function(){
$(this).css("transform","rotateY(0deg)"); //鼠标移开让旋转度数归零
var n=$(this).index();
$(".front").eq(n).css("display","inline-block");
$(".back").eq(n).hide();
})
})
</script>

posted @ 2017-09-05 21:07  周先生66  阅读(10365)  评论(0编辑  收藏  举报