haha1235  

2013年10月7日

摘要: #includeint main(void){ int denominator,flag,i,n; double item,sum; printf("Enter n:"); scanf("%d",&n); flag=1; denominator=1; sum=0; for(i=1;i<=n;i++){ item=flag*1.0/denomintor; sum=sum+item; flag=-flag; denominator= denominator+2 } printf("sum=%f\n",sum); ... 阅读全文
posted @ 2013-10-07 10:57 haha1235 阅读(104) 评论(0) 推荐(0) 编辑
 
摘要: #includeint main(void){ int i,n,sum; printf("Enter n:"); scanf("%d",&n); sum=0; for(i=1;i<=n;i++){ sum=sum+i; } printf("Sum of numbers from 1 to %d is %d\n",n,sum); return 0;} 阅读全文
posted @ 2013-10-07 10:53 haha1235 阅读(87) 评论(0) 推荐(0) 编辑
 
摘要: #includeint main(void){ int fahr,lower,upper; double celsius; printf("Enter lower:"); scanf("%d",&lower); printf("Enter upper:"); scanf("%d",&upper); printf("fahr celsius\n"); for(fahr=lower;fahr<=upper;fahr++){ celsius=(5.0/9.0)*(fahr-32) 阅读全文
posted @ 2013-10-07 10:52 haha1235 阅读(86) 评论(0) 推荐(0) 编辑
 
摘要: #include#includeint main(void){ int money,year; double rate,sum; printf("Enter money:"); scanf("%d",&money); printf("Enter year:"); scanf("%d",&year); printf("Enter rate:"); scanf("%If",&rate); sum=money*pow(1+rate,year); print( 阅读全文
posted @ 2013-10-07 10:49 haha1235 阅读(68) 评论(0) 推荐(0) 编辑
 
摘要: #includeint main(void){ double x,y; printf("Enter x(x>=0):\n"); scanf("%lf",&x); if(x<=15){ y=4*x/3; } else{ y=2.5*x-10.5; } printf("y=f(%f)=%.2f\n",x,y); return 0;} 阅读全文
posted @ 2013-10-07 10:48 haha1235 阅读(75) 评论(0) 推荐(0) 编辑
 
摘要: #includeint main(void){ int celsius,fahr; fahr=100; celsius=5*(fahr-32)/9; printf("fahr=%d,celsius=%d\n",fahr,celsius); return 0;} 阅读全文
posted @ 2013-10-07 10:44 haha1235 阅读(103) 评论(0) 推荐(0) 编辑
 
摘要: #includeint main(void){ printf("Hello World!\n"); return 0;} 阅读全文
posted @ 2013-10-07 10:41 haha1235 阅读(73) 评论(0) 推荐(0) 编辑
 
摘要: #includeint main(void){ printf("Programming is fun.\n"); printf("And programming in C is even more fun\n"); return 0;} 阅读全文
posted @ 2013-10-07 10:41 haha1235 阅读(101) 评论(0) 推荐(0) 编辑
 
摘要: #includeint main(void){ int n; int factorial(int n); scanf_s("%d",&n); printf("%d\n",factorial(n)); return 0;}int factorial(int n){ int i,fact=1; for(i=1;i<=n;i++) fact=fact*i; return fact;} 阅读全文
posted @ 2013-10-07 10:36 haha1235 阅读(121) 评论(0) 推荐(0) 编辑

2013年10月5日

摘要: #include int main(void){ void pyramid(int n); pyramid(5); return 0;} void pyramid(int n) { int i,j; for(i=1;i<=n;i++){ for(j=1;j<=n-i;j++) printf(" "); for(j=1;j<=i;j++) printf("%d",i); putchar('\n'); } } 阅读全文
posted @ 2013-10-05 22:50 haha1235 阅读(116) 评论(0) 推荐(0) 编辑