摘要:
前中后序的相互转换只需要考虑对应的子树是否存在节点即可,有中序的顺序判断子树关系,由前(开始为根)或后(末尾为根)序遍历判断当前子树的根是哪个节点; 阅读全文
2019年10月20日
摘要:
Recommendation system predicts the preference that a user would give to an item. Now you are asked to program a very simple recommendation system that 阅读全文
2019年10月19日
摘要:
In the big cities, the subway systems always look so complex to the visitors. To give you some sense, the following figure shows the map of Beijing su 阅读全文
2019年10月17日
摘要:
#include<iostream> #include<sstream>#include<string>using namespace std;int n;bool judge(string s){ long long t1, t2, t3; stringstream ss; /*ss.clear( 阅读全文
2019年10月15日
摘要:
#include <iostream>#include <vector>using namespace std;int main() { int n, m, k, nv, a, b, num; scanf("%d%d", &n, &m); vector<int> v[n]; for (int i = 阅读全文
摘要:
#include<iostream>#include<string>#include<algorithm>using namespace std;string rev(string s){ reverse(s.begin(), s.end()); return s;}string add(strin 阅读全文
2019年10月11日
摘要:
After each PAT, the PAT Center will announce the ranking of institutions based on their students’ performances. Now you are asked to generate the rank 阅读全文
2019年10月10日
摘要:
#include<iostream> #include<stdio.h> #include<vector> #include<algorithm> #include<time.h> #include<set> #pragma warning(disable:4996) using namespace std; struct coordinate { int x, y; }; bool cmp_x( 阅读全文
摘要:
This is a problem given in the Graduate Entrance Exam in 2018: Which of the following is NOT a topological order obtained from the given directed grap 阅读全文
2019年10月9日
摘要:
The lowest common ancestor (LCA) of two nodes U and V in a tree is the deepest node that has both U and V as descendants. Given any two nodes in a bin 阅读全文